+ int i, ord;
+
+ if (pos < 0 || pos >= bits || !test_bit(pos, buf))
+ return -1;
+
+ i = find_first_bit(buf, bits);
+ ord = 0;
+ while (i < pos) {
+ i = find_next_bit(buf, bits, i + 1);
+ ord++;
+ }
+ BUG_ON(i != pos);
+
+ return ord;
+}
+
+/**
+ * bitmap_ord_to_pos - find position of n-th set bit in bitmap
+ * @buf: pointer to bitmap
+ * @ord: ordinal bit position (n-th set bit, n >= 0)
+ * @bits: number of valid bit positions in @buf
+ *
+ * Map the ordinal offset of bit @ord in @buf to its position in @buf.
+ * Value of @ord should be in range 0 <= @ord < weight(buf), else
+ * results are undefined.
+ *
+ * If for example, just bits 4 through 7 are set in @buf, then @ord
+ * values 0 through 3 will get mapped to 4 through 7, respectively,
+ * and all other @ord values return undefined values. When @ord value 3
+ * gets mapped to (returns) @pos value 7 in this example, that means
+ * that the 3rd set bit (starting with 0th) is at position 7 in @buf.
+ *
+ * The bit positions 0 through @bits are valid positions in @buf.
+ */
+static int bitmap_ord_to_pos(const unsigned long *buf, int ord, int bits)
+{
+ int pos = 0;
+
+ if (ord >= 0 && ord < bits) {
+ int i;
+
+ for (i = find_first_bit(buf, bits);
+ i < bits && ord > 0;
+ i = find_next_bit(buf, bits, i + 1))
+ ord--;
+ if (i < bits && ord == 0)
+ pos = i;
+ }
+
+ return pos;
+}
+
+/**
+ * bitmap_remap - Apply map defined by a pair of bitmaps to another bitmap
+ * @dst: remapped result
+ * @src: subset to be remapped
+ * @old: defines domain of map
+ * @new: defines range of map
+ * @bits: number of bits in each of these bitmaps
+ *
+ * Let @old and @new define a mapping of bit positions, such that
+ * whatever position is held by the n-th set bit in @old is mapped
+ * to the n-th set bit in @new. In the more general case, allowing
+ * for the possibility that the weight 'w' of @new is less than the
+ * weight of @old, map the position of the n-th set bit in @old to
+ * the position of the m-th set bit in @new, where m == n % w.
+ *
+ * If either of the @old and @new bitmaps are empty, or if @src and
+ * @dst point to the same location, then this routine copies @src
+ * to @dst.
+ *
+ * The positions of unset bits in @old are mapped to themselves
+ * (the identify map).
+ *
+ * Apply the above specified mapping to @src, placing the result in
+ * @dst, clearing any bits previously set in @dst.
+ *
+ * For example, lets say that @old has bits 4 through 7 set, and
+ * @new has bits 12 through 15 set. This defines the mapping of bit
+ * position 4 to 12, 5 to 13, 6 to 14 and 7 to 15, and of all other
+ * bit positions unchanged. So if say @src comes into this routine
+ * with bits 1, 5 and 7 set, then @dst should leave with bits 1,
+ * 13 and 15 set.
+ */
+void bitmap_remap(unsigned long *dst, const unsigned long *src,
+ const unsigned long *old, const unsigned long *new,
+ int bits)
+{
+ int oldbit, w;
+
+ if (dst == src) /* following doesn't handle inplace remaps */
+ return;
+ bitmap_zero(dst, bits);
+
+ w = bitmap_weight(new, bits);
+ for_each_set_bit(oldbit, src, bits) {
+ int n = bitmap_pos_to_ord(old, oldbit, bits);
+
+ if (n < 0 || w == 0)
+ set_bit(oldbit, dst); /* identity map */
+ else
+ set_bit(bitmap_ord_to_pos(new, n % w, bits), dst);
+ }
+}
+EXPORT_SYMBOL(bitmap_remap);
+
+/**
+ * bitmap_bitremap - Apply map defined by a pair of bitmaps to a single bit
+ * @oldbit: bit position to be mapped
+ * @old: defines domain of map
+ * @new: defines range of map
+ * @bits: number of bits in each of these bitmaps
+ *
+ * Let @old and @new define a mapping of bit positions, such that
+ * whatever position is held by the n-th set bit in @old is mapped
+ * to the n-th set bit in @new. In the more general case, allowing
+ * for the possibility that the weight 'w' of @new is less than the
+ * weight of @old, map the position of the n-th set bit in @old to
+ * the position of the m-th set bit in @new, where m == n % w.
+ *
+ * The positions of unset bits in @old are mapped to themselves
+ * (the identify map).
+ *
+ * Apply the above specified mapping to bit position @oldbit, returning
+ * the new bit position.
+ *
+ * For example, lets say that @old has bits 4 through 7 set, and
+ * @new has bits 12 through 15 set. This defines the mapping of bit
+ * position 4 to 12, 5 to 13, 6 to 14 and 7 to 15, and of all other
+ * bit positions unchanged. So if say @oldbit is 5, then this routine
+ * returns 13.
+ */
+int bitmap_bitremap(int oldbit, const unsigned long *old,
+ const unsigned long *new, int bits)
+{
+ int w = bitmap_weight(new, bits);
+ int n = bitmap_pos_to_ord(old, oldbit, bits);
+ if (n < 0 || w == 0)
+ return oldbit;
+ else
+ return bitmap_ord_to_pos(new, n % w, bits);
+}
+EXPORT_SYMBOL(bitmap_bitremap);
+
+/**
+ * bitmap_onto - translate one bitmap relative to another
+ * @dst: resulting translated bitmap
+ * @orig: original untranslated bitmap
+ * @relmap: bitmap relative to which translated
+ * @bits: number of bits in each of these bitmaps
+ *
+ * Set the n-th bit of @dst iff there exists some m such that the
+ * n-th bit of @relmap is set, the m-th bit of @orig is set, and
+ * the n-th bit of @relmap is also the m-th _set_ bit of @relmap.
+ * (If you understood the previous sentence the first time your
+ * read it, you're overqualified for your current job.)
+ *
+ * In other words, @orig is mapped onto (surjectively) @dst,
+ * using the the map { <n, m> | the n-th bit of @relmap is the
+ * m-th set bit of @relmap }.
+ *
+ * Any set bits in @orig above bit number W, where W is the
+ * weight of (number of set bits in) @relmap are mapped nowhere.
+ * In particular, if for all bits m set in @orig, m >= W, then
+ * @dst will end up empty. In situations where the possibility
+ * of such an empty result is not desired, one way to avoid it is
+ * to use the bitmap_fold() operator, below, to first fold the
+ * @orig bitmap over itself so that all its set bits x are in the
+ * range 0 <= x < W. The bitmap_fold() operator does this by
+ * setting the bit (m % W) in @dst, for each bit (m) set in @orig.
+ *
+ * Example [1] for bitmap_onto():
+ * Let's say @relmap has bits 30-39 set, and @orig has bits
+ * 1, 3, 5, 7, 9 and 11 set. Then on return from this routine,
+ * @dst will have bits 31, 33, 35, 37 and 39 set.
+ *
+ * When bit 0 is set in @orig, it means turn on the bit in
+ * @dst corresponding to whatever is the first bit (if any)
+ * that is turned on in @relmap. Since bit 0 was off in the
+ * above example, we leave off that bit (bit 30) in @dst.
+ *
+ * When bit 1 is set in @orig (as in the above example), it
+ * means turn on the bit in @dst corresponding to whatever
+ * is the second bit that is turned on in @relmap. The second
+ * bit in @relmap that was turned on in the above example was
+ * bit 31, so we turned on bit 31 in @dst.
+ *
+ * Similarly, we turned on bits 33, 35, 37 and 39 in @dst,
+ * because they were the 4th, 6th, 8th and 10th set bits
+ * set in @relmap, and the 4th, 6th, 8th and 10th bits of
+ * @orig (i.e. bits 3, 5, 7 and 9) were also set.
+ *
+ * When bit 11 is set in @orig, it means turn on the bit in
+ * @dst corresponding to whatever is the twelth bit that is
+ * turned on in @relmap. In the above example, there were
+ * only ten bits turned on in @relmap (30..39), so that bit
+ * 11 was set in @orig had no affect on @dst.
+ *
+ * Example [2] for bitmap_fold() + bitmap_onto():
+ * Let's say @relmap has these ten bits set:
+ * 40 41 42 43 45 48 53 61 74 95
+ * (for the curious, that's 40 plus the first ten terms of the
+ * Fibonacci sequence.)
+ *
+ * Further lets say we use the following code, invoking
+ * bitmap_fold() then bitmap_onto, as suggested above to
+ * avoid the possitility of an empty @dst result:
+ *
+ * unsigned long *tmp; // a temporary bitmap's bits
+ *
+ * bitmap_fold(tmp, orig, bitmap_weight(relmap, bits), bits);
+ * bitmap_onto(dst, tmp, relmap, bits);
+ *
+ * Then this table shows what various values of @dst would be, for
+ * various @orig's. I list the zero-based positions of each set bit.
+ * The tmp column shows the intermediate result, as computed by
+ * using bitmap_fold() to fold the @orig bitmap modulo ten
+ * (the weight of @relmap).
+ *
+ * @orig tmp @dst
+ * 0 0 40
+ * 1 1 41
+ * 9 9 95
+ * 10 0 40 (*)
+ * 1 3 5 7 1 3 5 7 41 43 48 61
+ * 0 1 2 3 4 0 1 2 3 4 40 41 42 43 45
+ * 0 9 18 27 0 9 8 7 40 61 74 95
+ * 0 10 20 30 0 40
+ * 0 11 22 33 0 1 2 3 40 41 42 43
+ * 0 12 24 36 0 2 4 6 40 42 45 53
+ * 78 102 211 1 2 8 41 42 74 (*)
+ *
+ * (*) For these marked lines, if we hadn't first done bitmap_fold()
+ * into tmp, then the @dst result would have been empty.
+ *
+ * If either of @orig or @relmap is empty (no set bits), then @dst
+ * will be returned empty.
+ *
+ * If (as explained above) the only set bits in @orig are in positions
+ * m where m >= W, (where W is the weight of @relmap) then @dst will
+ * once again be returned empty.
+ *
+ * All bits in @dst not set by the above rule are cleared.
+ */
+void bitmap_onto(unsigned long *dst, const unsigned long *orig,
+ const unsigned long *relmap, int bits)
+{
+ int n, m; /* same meaning as in above comment */
+
+ if (dst == orig) /* following doesn't handle inplace mappings */
+ return;
+ bitmap_zero(dst, bits);
+
+ /*
+ * The following code is a more efficient, but less
+ * obvious, equivalent to the loop:
+ * for (m = 0; m < bitmap_weight(relmap, bits); m++) {
+ * n = bitmap_ord_to_pos(orig, m, bits);
+ * if (test_bit(m, orig))
+ * set_bit(n, dst);
+ * }
+ */
+
+ m = 0;
+ for_each_set_bit(n, relmap, bits) {
+ /* m == bitmap_pos_to_ord(relmap, n, bits) */
+ if (test_bit(m, orig))
+ set_bit(n, dst);
+ m++;
+ }
+}
+EXPORT_SYMBOL(bitmap_onto);
+
+/**
+ * bitmap_fold - fold larger bitmap into smaller, modulo specified size
+ * @dst: resulting smaller bitmap
+ * @orig: original larger bitmap
+ * @sz: specified size
+ * @bits: number of bits in each of these bitmaps
+ *
+ * For each bit oldbit in @orig, set bit oldbit mod @sz in @dst.
+ * Clear all other bits in @dst. See further the comment and
+ * Example [2] for bitmap_onto() for why and how to use this.
+ */
+void bitmap_fold(unsigned long *dst, const unsigned long *orig,
+ int sz, int bits)
+{
+ int oldbit;
+
+ if (dst == orig) /* following doesn't handle inplace mappings */
+ return;
+ bitmap_zero(dst, bits);
+
+ for_each_set_bit(oldbit, orig, bits)
+ set_bit(oldbit % sz, dst);
+}
+EXPORT_SYMBOL(bitmap_fold);
+
+/*
+ * Common code for bitmap_*_region() routines.
+ * bitmap: array of unsigned longs corresponding to the bitmap
+ * pos: the beginning of the region
+ * order: region size (log base 2 of number of bits)
+ * reg_op: operation(s) to perform on that region of bitmap
+ *
+ * Can set, verify and/or release a region of bits in a bitmap,
+ * depending on which combination of REG_OP_* flag bits is set.
+ *
+ * A region of a bitmap is a sequence of bits in the bitmap, of
+ * some size '1 << order' (a power of two), aligned to that same
+ * '1 << order' power of two.
+ *
+ * Returns 1 if REG_OP_ISFREE succeeds (region is all zero bits).
+ * Returns 0 in all other cases and reg_ops.
+ */